Al aaap ap1274

Only terms with a = p that satisfy «a — «p = ±«21 survive the time integration. We get

£1^2 = TJ I V1 2 I (aa a p aa ap)8(«21 + «a — «p)

= T2 IV1 2 I [n(«a)(n(«p) + 1)8(«21 + «a — «p)

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